Percentage

Chapter 8 Study Notes · O-Level 4052

Section 7 of 10
Contents

8.6Reverse Percentage

The value you are given is the one after the change, and you work back to the original. Set the original at 100%100\% and go through 1%1\%:

  1. Say what percentage of the original you were given. After a 25%25\% increase, the new price is 125%125\% of the original.
  2. Divide by that percentage to get 1%1\% of the original.
  3. Multiply by 100100 to get the original itself.

Reverse percentage: finding the original after an increase

After a 25%\displaystyle 25\% increase in price, a pair of sports shoes now costs $175\displaystyle \$175. Find the original price.

Show solution
The original price is 100%100\%, so after a 25%25\% increase the new price is 125%125\%.
125% of original\displaystyle 125\% \text{ of original}
=$175\displaystyle = \$175
1% of original\displaystyle 1\% \text{ of original}
=175125\displaystyle = \dfrac{175}{125}
100% of original\displaystyle 100\% \text{ of original}
=175125×100\displaystyle = \dfrac{175}{125} \times 100
=$140\displaystyle = \$140
paid: $490discount70%30%marked price = 100%the $490 is 70% of the bar, not the whole of it
The example below. The $490\$490 is the 70%70\% part, so one part is 490÷70490 \div 70 and the whole is one hundred of those.

Reverse percentage: finding the original after a decrease

During a sale, a phone was sold at a 30%\displaystyle 30\% discount for $490\displaystyle \$490. Find the original marked price.

Show solution
The marked price is 100%100\%, so after a 30%30\% discount the sale price is 70%70\%.
70% of marked price\displaystyle 70\% \text{ of marked price}
=$490\displaystyle = \$490
1% of marked price\displaystyle 1\% \text{ of marked price}
=49070\displaystyle = \dfrac{490}{70}
100% of marked price\displaystyle 100\% \text{ of marked price}
=49070×100\displaystyle = \dfrac{490}{70} \times 100
=$700\displaystyle = \$700

Now you try

After an increase of 25%25\%, a salary is $3125\$3\,125. Find the original salary.

Show solution
Let the original salary be xx.
x×(1+25100)\displaystyle x \times \left(1 + \dfrac{25}{100}\right)
=3125\displaystyle = 3125
x×1.25\displaystyle x \times 1.25
=3125\displaystyle = 3125
x\displaystyle x
=31251.25\displaystyle = \dfrac{3125}{1.25}
x\displaystyle x
=$2500\displaystyle = \$2\,500

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