Percentage

Chapter 8 Study Notes · O-Level 4052

Section 6 of 10
Contents

8.5Percentage Change

Percentage change measures how much a quantity has increased or decreased relative to its original value.

Percentage change
Percentage change=New valueOriginal valueOriginal value×100%\displaystyle \text{Percentage change} = \dfrac{\text{New value} - \text{Original value}}{\text{Original value}} \times 100\%
  • A positive result is a percentage increase.
  • A negative result is a percentage decrease.
ChangeMultiplierNew value
Increase by r%r\%1+r1001 + \dfrac{r}{100}Old×(1+r100)\text{Old} \times \left(1 + \dfrac{r}{100}\right)
Decrease by r%r\%1r1001 - \dfrac{r}{100}Old×(1r100)\text{Old} \times \left(1 - \dfrac{r}{100}\right)

Calculating percentage increase

The number of visitors to a hawker centre increased from 2400\displaystyle 2400 to 2760\displaystyle 2760 in one month. Find the percentage increase.

Show solution
Increase\displaystyle \text{Increase}
=27602400\displaystyle = 2760 - 2400
=360\displaystyle = 360
Percentage increase\displaystyle \text{Percentage increase}
=3602400×100%\displaystyle = \dfrac{360}{2400} \times 100\%
=15%\displaystyle = 15\%

Finding the new value after a percentage decrease

A data plan originally provided 10\displaystyle 10 GB of data per month. The provider reduces this by 8%\displaystyle 8\% for a promotional tier. How much data does the new plan provide?

Show solution
New data\displaystyle \text{New data}
=(1008)% of 10 GB\displaystyle = (100 - 8)\% \text{ of } 10 \text{ GB}
=92% of 10 GB\displaystyle = 92\% \text{ of } 10 \text{ GB}
=92100×10\displaystyle = \dfrac{92}{100} \times 10
=9.2 GB\displaystyle = 9.2 \text{ GB}

Now you try

An item costs $150\$150. The price increased by 10%10\%. Find the new price.

Show solution
New price\displaystyle \text{New price}
=150×(1+10100)\displaystyle = 150 \times \left(1 + \dfrac{10}{100}\right)
=150×1.10\displaystyle = 150 \times 1.10
=$165\displaystyle = \$165

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