Basic Algebra and Algebraic Manipulation

Chapter 4 Study Notes · O-Level 4052

Section 6 of 8
Contents

4.5Factorisation

Factorisation is the reverse of expansion. Instead of distributing a factor into a bracket, we extract a common factor out of the terms.

Factorisation
ab+ac=a(b+c)ab + ac = a(b + c)
Recall: HCF from Chapter 1, the HCF of the numerical coefficients becomes the common factor you take out.

Numerical common factor

Factorise 15y21\displaystyle 15y - 21 completely.

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HCF of 1515 and 2121 is 33.
15y21=3(5y7)15y - 21 = 3(5y - 7)

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Factorise 10x410x - 4.

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HCF of 1010 and 44 is 22.
10x4=2(5x2)10x - 4 = 2(5x - 2)

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Variable common factor

Factorise 12mn28m2n\displaystyle 12mn^2 - 8m^2n completely.

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Common factors: HCF of 1212 and 88 is 44; both terms contain mm and nn.
HCF =4mn= 4mn.
12mn28m2n=4mn(3n2m)12mn^2 - 8m^2n = 4mn(3n - 2m)

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Factorise 10x+10y-10x + 10y.

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Take out 10-10 as a common factor:
10x+10y=10(xy)-10x + 10y = -10(x - y)

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Factorise first, then evaluate

(a) Factorise 8a2+12a\displaystyle 8a^2 + 12a completely. (b) Hence evaluate 8a2+12a\displaystyle 8a^2 + 12a when a=50\displaystyle a = 50.

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(a) HCF of 88 and 1212 is 44; both terms contain aa, so the HCF is 4a4a.
8a2+12a\displaystyle 8a^2 + 12a
=4a(2a+3)\displaystyle = 4a(2a + 3)
(b) Substitute a=50a = 50:
4a(2a+3)\displaystyle 4a(2a + 3)
=200×103\displaystyle = 200 \times 103
=20600\displaystyle = 20\,600
The factorised form turns the sum into one easy product.

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