Ratio and Rate

Secondary 1 practice

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Ratio and Rate practice questions

Secondary 1 topics, the foundation the O-Level Mathematics 4052 syllabus builds on. Every question below has a full worked solution.

When a student gets a question wrong in Math Amigo, it does not show the answer straight away. It reads the working, identifies the step that went wrong, and asks a question that points at the correction. The worked solution is there once a genuine attempt has been made.

Practise Ratio and Rate free

What this topic covers

Worked examples

Example 1

Simplify the ratio 6:15:66 : 15 : 6.
Show the worked solution
  • 6:15:66 : 15 : 6
  • =63:153:63divide all by 3= \frac{6}{3} : \frac{15}{3} : \frac{6}{3} \quad \scriptsize\textit{divide all by 3}
  • =2:5:2= 2 : 5 : 2

Answer: 2:5:22 : 5 : 2

Example 2

Pack A: 4 pens for $8.80\$8.80. Pack B: 12 pens for $30.60\$30.60. Find the unit price, in dollars, of the pack that offers better value, that is the lower price per item. Give your answer correct to 2 decimal places if necessary.
Show the worked solution
  • Pack A: $8.804=$2.20 each\text{Pack A: } \frac{\$8.80}{4} = \$2.20 \text{ each}
  • Pack B: $30.6012=$2.55 each\text{Pack B: } \frac{\$30.60}{12} = \$2.55 \text{ each}
  • Pack A is cheaper at $2.20 each\text{Pack A is cheaper at } \$2.20 \text{ each}

Answer: 2.202.20

Example 3

$1000\$1000 is invested for 55 years and earns $400\$400 in simple interest. Find the annual interest rate.
Show the worked solution
  • I=P×R×T100I = \frac{P \times R \times T}{100}
  • 400=1000×R×5100400 = \frac{1000 \times R \times 5}{100}
  • R=400×1001000×5R = \frac{400 \times 100}{1000 \times 5}
  • =8%= 8\%

Answer: 88

Questions parents ask

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Which syllabus does this follow?

O-Level Mathematics (4052), for Singapore secondary students. Math Amigo covers Secondary 1 to 4, both O-Level Mathematics and Additional Mathematics.

Will it just show my child the answer?

No. On a wrong answer it looks at the working, points to the step that went wrong, and asks a question that helps the student find the correction. The full worked solution is available after a genuine attempt.

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