Integers, Rational Numbers and Real Numbers

Chapter 2 Study Notes

Section 3 of 8
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2.2Addition and Subtraction of Integers

With negatives in play the number line runs both ways, so you can move left past 00.

Owe $2\$2 and borrow $3\$3 more and you owe $5\$5. Have $5\$5 and owe $2\$2 and you are $3\$3 up.

Adding two negatives
(a)+(b)=(a+b)(-a) + (-b) = -(a + b)
Adding a negative to a positive
a+(b)=aba + (-b) = a - b
Subtracting a negative
a(b)=a+ba - (-b) = a + b

Temperature drop

At noon it was 5C-5\,^{\circ}\text{C}. By midnight it had fallen a further 9C9\,^{\circ}\text{C}. Find the midnight temperature.

Show solution
Falling 9C9\,^{\circ}\text{C} means subtracting: (5)+(9)(-5) + (-9).
Both moves go the same way down, so the falls add: 5+9=145 + 9 = 14 below zero.
Result is negative: (5)+(9)=14(-5) + (-9) = -14.
The midnight temperature was 14C-14\,^{\circ}\text{C}.

Altitude calculation

A submarine at 120-120 m rises 4545 m, then dives 3030 m. Find its final position relative to sea level.

Show solution
Start: 120-120 m.
Rise 4545 m: 120+45=75-120 + 45 = -75 m.
Dive 3030 m: 75+(30)=105-75 + (-30) = -105 m.
Final position: 105-105 m, that is a depth of 105105 m below sea level.

Paying off an overdraft

Ali's bank balance is $85-\$85 (overdrawn). He deposits $120\$120. What is his new balance?

Show solution
(85)+120=12085=35(-85) + 120 = 120 - 85 = 35.
His new balance is $35\$35.

Finding the starting temperature (reverse problem)

A temperature rose by 11C11\,^{\circ}\text{C} to reach 3C-3\,^{\circ}\text{C}. Find where it started.

Show solution
A rise of 1111 took it to 3-3, so go back down 1111 from 3-3.
311=14-3 - 11 = -14
It started at 14C-14\,^{\circ}\text{C}.
Check: 14+11=3-14 + 11 = -3.

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